15c^2-20c+5=0

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Solution for 15c^2-20c+5=0 equation:


Simplifying
15c2 + -20c + 5 = 0

Reorder the terms:
5 + -20c + 15c2 = 0

Solving
5 + -20c + 15c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '5'.
5(1 + -4c + 3c2) = 0

Factor a trinomial.
5((1 + -3c)(1 + -1c)) = 0

Ignore the factor 5.

Subproblem 1

Set the factor '(1 + -3c)' equal to zero and attempt to solve: Simplifying 1 + -3c = 0 Solving 1 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -3c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -3c = 0 + -1 -3c = 0 + -1 Combine like terms: 0 + -1 = -1 -3c = -1 Divide each side by '-3'. c = 0.3333333333 Simplifying c = 0.3333333333

Subproblem 2

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Solution

c = {0.3333333333, 1}

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